下⾯程序的时间复杂度为( )
int record_choose[MAXN][MAXN];
int choose(int n, int m){
if (m == 0 || m == n)
return 1;
if (record_choose[n][m] == 0)
return record_choose[n][m] = choose(n - 1, m - 1) + choose(n - 1, m);
return record_choose[n][m];
}
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